Reversible Work Theorem

The theorem states that the radial distribution function g(r) determines the reversible work w(r) associated with the process by which two particles in a fluid are moved from an infinite separation to a separation r, according to the following equation:
$\displaystyle g(r)=$exp$\displaystyle (-\beta w(r)).$ (393)

Note that since the process is reversible at constant T, N and V, $ w(r) =\Delta A$, where A is the Helmholtz free energy.

Proof:

Consider the mean force between particles 1 and 2, averaged over the equilibrium distribution of all other particles,

$\displaystyle -<\frac{d V(r^N)}{dr_1}>_{r_1 r_2} = \frac{-\int \frac{dV}{dr_1} e^{-\beta V(r^N)} dr_3 ... dr_N }{\int e^{-\beta V(r^N)} dr_3 ... dr_N},$ (394)
which gives
$\displaystyle -<\frac{d V(r^N)}{dr_1}>_{r_1 r_2} =\frac{1}{\beta} \frac{d}{dr_1}$ln$\displaystyle \int e^{-\beta V(r^N)} dr_3 ... dr_N,$ (395)
or
$\displaystyle -<\frac{d V(r^N)}{dr_1}>_{r_1 r_2} = +\frac{1}{\beta} \frac{d}{dr_1}$   ln$\displaystyle \frac{N(N+1)}{Z} + \frac{1}{\beta} \frac{d}{dr_1}$ln$\displaystyle \int e^{-\beta V(r^N)} dr_3 ... dr_N,$ (396)
since both the number of particles N in the system and the partition function Z are constants. Eq. (396) can be simplified according to Eqs. (388) and (389) as follows,
$\displaystyle -<\frac{d V(r^N)}{dr_1}>_{r_1 r_2} =\frac{1}{\beta} \frac{d}{dr_1}$   ln$\displaystyle g(r_1).$ (397)
Integration of the expression for the average force, introduced by Eq. (397), gives the reversible work,
$\displaystyle w(r_{12}) = \int_{r_{12}}^{\infty} dr_1 (-<\frac{d V(r^N)}{dr_1}>) = k T \int_{r_{12}}^{\infty} dr_1 \frac{d}{dr_1}$   ln$\displaystyle g(r_1),$ (398)

Therefore, the reversible work $ w(r_{12})$ associated with the process by which particles 1 and 2 are moved from infinite separation to a relative separation $ r_{12}$ is

$\displaystyle w(r_{12}) = k T$   ln$\displaystyle g(\infty) - k T$   ln$\displaystyle g(r_{12})=- k T$   ln$\displaystyle g(r_{12}),$ (399)

since $ g(\infty)=1$.

Finally, note that

$\displaystyle w(r) = k T$   ln$\displaystyle \frac{Z(r_{12}=\infty)}{Z(r_{12}=r)} = -(A (r_{12}= \infty) - A(r_{12}=r)),$ (400)
where $ Z(r_{12}=r)$ and $ A(r_{12}=r)$ are the canonical partition function and the Helmholtz free energy of the system, subject to the constraint of fixed relative distance $ r_{12}=r$ between particles 1 and 2.