Density Operator

In this section we show that ensemble averages for both pure and mixed states can be computed as follows,
$\displaystyle A = Tr\{\hat{\rho} \hat{A}\},$ (10)


where $ \hat{\rho}$ is the density operator

$\displaystyle \hat{\rho} = \sum_k p_k \vert\phi_k><\phi_k\vert.$ (11)


Note that, in particular, the density operator of an ensemble where all of the replica systems are described by the same state vector $ \vert\psi>$ (i.e., a pure state) is

$\displaystyle \hat{\rho} = \vert\psi><\psi \vert.$ (12)


Eq. (10) can be proved first for a pure state $ \vert\psi> = \sum_k a_k \vert\phi_k >$, where $ \mid \phi_k \rangle$ constitute a complete basis set of orthonormal states (i.e., $ <\phi_{k'}\vert\phi_k>=\delta_{kk'}$), by computing the Tr$ \{\hat{\rho} \hat{A}\}$ in such representation as follows,

$\displaystyle A = \sum_{k'} <\phi_{k'}\vert\psi><\psi\vert\hat{A}\vert\phi_{k'}>.$ (13)


Substituting the expansion of $ \mid \psi \rangle$ into Eq. (13) we obtain,

$\displaystyle A = \sum_{k'} \sum_j \sum_k <\phi_{k'}\vert\phi_k> a_k a_j^* <\phi_j\vert\hat{A}\vert\phi_{k'}>,$ (14)


and since $ <\phi_{k'}\vert\phi_k>=\delta_{kk'}$,

$\displaystyle A = \sum_k p_k <\phi_k\vert\hat{A}\vert\phi_k> + \sum_k \sum_{j \neq k} \sqrt{p_k p_j} e^{i(\theta_k - \theta_j)} <\phi_j\vert\hat{A}\vert\phi_k>,$ (15)


where we have substituted the expansion coefficients $ a_j$ in accord with Eq. (4). Equation (15) is identical to Eq. (6) and, therefore, Eq. (10) is identical to Eq. (6) which defines an ensemble average for a pure state. Eq. (10) can also be proved for an arbitrary mixed state defined by the density operator introduced by Eq. (11), by computing the Tr$ \{\hat{\rho} \hat{A}\}$ as follows,

$\displaystyle A = \sum_{k'} \sum_k p_k <\phi_{k'}\vert\phi_k> <\phi_k\vert\hat{A}\vert\phi_{k'}> = \sum_k p_k <\phi_k \vert\hat{A}\vert \phi_k>,$ (16)


which is identical to Eq. (7).

Exercise 2:
(A) Show that Tr$ \{\hat{\rho}\}$=1 for both mixed and pure states.
(B) Show that Tr$ \{\hat{\rho}^2\}$=1 for pure states.
(C) Show that Tr$ \{\hat{\rho}^2\} \leq 1$ for mixed states.

Note that the Tr$ \{\hat{\rho}^2\}$ is, therefore, a measurement of decoherence (i.e., lost of interference between the various different states in the ensemble). When the system is in a coherent superposition state, such as the one described by Eq. (2), Tr$ \{\hat{\rho}^2\}$=1. However, Tr$ \{\hat{\rho}^2\} \le$1 when the system is in an incoherent superposition of states such as the one described by Eq. (9).